[POWERPC] Fixup softirq preempt count

This fixes the handling of the preempt count when switching
interrupt stacks so that HW interrupt properly get the softirq
mask copied over from the previous stack.

It also initializes the softirq stack preempt_count to 0 instead
of SOFTIRQ_OFFSET, like x86, as __do_softirq() does the increment,
and we hit some lockdep checks if we have it twice.

That means we do run for a little while off the softirq stack
with the preempt-count set to 0, which could be deadly if we
try to take a softirq at that point, however we do so with
interrupts disabled, so I think we are ok.

Signed-off-by: Benjamin Herrenschmidt <benh@kernel.crashing.org>
Signed-off-by: Paul Mackerras <paulus@samba.org>

1 files changed, 14 insertions, 1 deletions

diff --git a/arch/powerpc/kernel/irq.c b/arch/powerpc/kernel/irq.c
index 292163f5b39..4617b65d464 100644
--- a/arch/powerpc/kernel/irq.c
+++ b/arch/powerpc/kernel/irq.c
@@ -310,8 +310,21 @@ void do_IRQ(struct pt_regs *regs)
 				handler = &__do_IRQ;
 			irqtp->task = curtp->task;
 			irqtp->flags = 0;
+
+			/* Copy the softirq bits in preempt_count so that the
+			 * softirq checks work in the hardirq context.
+			 */
+			irqtp->preempt_count =
+				(irqtp->preempt_count & ~SOFTIRQ_MASK) |
+				(curtp->preempt_count & SOFTIRQ_MASK);
+
 			call_handle_irq(irq, desc, irqtp, handler);
 			irqtp->task = NULL;
+
+
+			/* Set any flag that may have been set on the
+			 * alternate stack
+			 */
 			if (irqtp->flags)
 				set_bits(irqtp->flags, &curtp->flags);
 		} else
@@ -357,7 +370,7 @@ void irq_ctx_init(void)
 		memset((void *)softirq_ctx[i], 0, THREAD_SIZE);
 		tp = softirq_ctx[i];
 		tp->cpu = i;
-		tp->preempt_count = SOFTIRQ_OFFSET;
+		tp->preempt_count = 0;
 
 		memset((void *)hardirq_ctx[i], 0, THREAD_SIZE);
 		tp = hardirq_ctx[i];