From c6b40d16d1cfa1a01158049bb887a9bbe48ef7ba Mon Sep 17 00:00:00 2001 From: Johannes Berg Date: Tue, 8 May 2007 00:27:20 -0700 Subject: fix sscanf %n match at end of input string I was playing with some code that sometimes got a string where a %n match should have been done where the input string ended, for example like this: sscanf("abc123", "abc%d%n", &a, &n); /* doesn't work */ sscanf("abc123a", "abc%d%n", &a, &n); /* works */ However, the scanf function in the kernel doesn't convert the %n in that case because it has already matched the complete input after %d and just completely stops matching then. This patch fixes that. [akpm@linux-foundation.org: cleanups] Signed-off-by: Johannes Berg Signed-off-by: Andrew Morton Signed-off-by: Linus Torvalds --- lib/vsprintf.c | 11 +++++++++++ 1 file changed, 11 insertions(+) (limited to 'lib/vsprintf.c') diff --git a/lib/vsprintf.c b/lib/vsprintf.c index cbab1df150c..01729024126 100644 --- a/lib/vsprintf.c +++ b/lib/vsprintf.c @@ -825,6 +825,17 @@ int vsscanf(const char * buf, const char * fmt, va_list args) break; str = next; } + + /* + * Now we've come all the way through so either the input string or the + * format ended. In the former case, there can be a %n at the current + * position in the format that needs to be filled. + */ + if (*fmt == '%' && *(fmt + 1) == 'n') { + int *p = (int *)va_arg(args, int *); + *p = str - buf; + } + return num; } -- cgit v1.2.3